125x^2-8=0

Solution for 125x^2-8=0 equation:

125x^2-8=0

a = 125; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·125·(-8)
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{10}}{2*125}=\frac{0-20\sqrt{10}}{250}
=-\frac{20\sqrt{10}}{250}
=-\frac{2\sqrt{10}}{25}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{10}}{2*125}=\frac{0+20\sqrt{10}}{250}
=\frac{20\sqrt{10}}{250}
=\frac{2\sqrt{10}}{25}
$